What is the derivative of x\sqrt[3]{1-x^2} ?

The derivative of x\sqrt[3]{1-x^2} is cube root of 1-x^2}-(2x^2)/(3(1-x^2)^{2/3)

What is the first derivative of x\sqrt[3]{1-x^2} ?

The first derivative of x\sqrt[3]{1-x^2} is cube root of 1-x^2}-(2x^2)/(3(1-x^2)^{2/3)

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derivative of

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d x}{d x} = 1

Simplify

\int \frac{sin ( lo g _{10} ( x ) )}{x} d x

\int \frac{1}{8} x^{2} d x

\int_{0}^{\infty} t e^{- s t} d t

- y^{^{'}} + \frac{4 y}{x} = \frac{y ^{2}}{x ^{3}}

What is the derivative of x\sqrt[3]{1-x^2} ?
The derivative of x\sqrt[3]{1-x^2} is cube root of 1-x^2}-(2x^2)/(3(1-x^2)^{2/3)
What is the first derivative of x\sqrt[3]{1-x^2} ?
The first derivative of x\sqrt[3]{1-x^2} is cube root of 1-x^2}-(2x^2)/(3(1-x^2)^{2/3)