What is (\partial)/(\partial x)(2ysin(x)) ?

The answer to (\partial)/(\partial x)(2ysin(x)) is 2ycos(x)

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(\partial)/(\partial x)(2ysin(x))

\frac{\partial}{\partial x} (2 y sin (x))

2 y cos (x)

Solution steps

\frac{\partial}{\partial x} (2 y sin (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= 2 y cos (x)

\int_{0}^{3} e^{x} sin (x) d x

f (x) = \frac{x ^{3}}{3} + \frac{1}{4 x}

\int e^{x^{3}} x^{5} d x

s (t) = \frac{9}{t ^{2} + 9 t - 3}

\int (\frac{1}{2 x ^{2}}) d x

What is (\partial)/(\partial x)(2ysin(x)) ?
The answer to (\partial)/(\partial x)(2ysin(x)) is 2ycos(x)