What is the limit as h approaches 0 of 1/(h+1) ?

The limit as h approaches 0 of 1/(h+1) is 1

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limit as h approaches 0 of 1/(h+1)

h \to 0 lim (\frac{1}{h + 1})

1

Solution steps

h \to 0 lim (\frac{1}{h + 1})

Plug in the value

h = 0

= \frac{1}{0 + 1}

Simplify

= 1

x^{2} + 2 x y - y^{2} + x = 6, (2, 4)

\int x^{- 3} (x + 1) d x

\int_{0}^{1} 8^{2 x} d x

\frac{\partial}{\partial y} (x \cdot sin (x + y))

(x^{2} + 6) y^{^{'}} = x y

What is the limit as h approaches 0 of 1/(h+1) ?
The limit as h approaches 0 of 1/(h+1) is 1