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Popular >

-4y^{''}+16y=0

Solution

- 4 y^{^{''}} + 16 y = 0

Solution

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

Solution steps

- 4 y^{''} (t) + 16 y = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

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Frequently Asked Questions (FAQ)

What is the solution for -4y^{''}+16y=0 ?
The solution for -4y^{''}+16y=0 is y=c_{1}e^{2t}+c_{2}e^{-2t}