What is the integral of (5^x+2^5) ?

The integral of (5^x+2^5) is (5^x)/(ln(5))+32x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (5^x+2^5)

\int (5^{x} + 2^{5}) d x

\frac{5 ^{x}}{ln ( 5 )} + 32 x + C

Solution steps

\int 5^{x} + 2^{5} d x

Simplify

= \int 5^{x} + 32 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5^{x} d x + \int 32 d x

\int 5^{x} d x = \frac{5 ^{x}}{ln ( 5 )}

\int 32 d x = 32 x

= \frac{5 ^{x}}{ln ( 5 )} + 32 x

Add a constant to the solution

= \frac{5 ^{x}}{ln ( 5 )} + 32 x + C

f (x) = 8 x e^{x} - 8 e^{x}

y = 3 x + 1, (8, 5)

\frac{d}{d x} (\frac{x ^{4}}{e ^{x}})

\frac{d}{d x} (x 4^{x})

x^{13}

What is the integral of (5^x+2^5) ?
The integral of (5^x+2^5) is (5^x)/(ln(5))+32x+C