What is the derivative of x^{1/3}+2x ?

The derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2

What is the first derivative of x^{1/3}+2x ?

The first derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2

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\frac{d}{d x} (x^{\frac{1}{3}} + 2 x)

\frac{1}{3 x ^{\frac{2}{3}}} + 2

Solution steps

\frac{d}{d x} (x^{\frac{1}{3}} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{1}{3}}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{\frac{1}{3}}) = \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (2 x) = 2

= \frac{1}{3 x ^{\frac{2}{3}}} + 2

\int_{0}^{9} x d x

f (x) = x^{4} + 2 x^{2}, at x = 1

\frac{d y}{d x} (x^{2} + 3) = x y

\int \frac{16 x ^{2} - 49}{x ^{3}} d x

\frac{( y - 3 )}{y ^{2} - 3 y + 9}

What is the derivative of x^{1/3}+2x ?
The derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2
What is the first derivative of x^{1/3}+2x ?
The first derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2