What is the sum from n=0 to infinity of (1/3)^n ?

The sum from n=0 to infinity of (1/3)^n is 3/2

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sum from n=0 to infinity of (1/3)^n

n = 0 \sum \infty (\frac{1}{3})^{n}

\frac{3}{2}

Solution steps

n = 0 \sum \infty (\frac{1}{3})^{n}

Apply Series Geometric Test:

\frac{3}{2}

= \frac{3}{2}

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What is the sum from n=0 to infinity of (1/3)^n ?
The sum from n=0 to infinity of (1/3)^n is 3/2