What is the solution for (y+4)*y^'=2xy+4y,y(2)=1 ?

The solution for (y+4)*y^'=2xy+4y,y(2)=1 is y+4ln(y)=x^2+4x-11

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(y+4)*y^'=2xy+4y,y(2)=1

(y + 4) \cdot y^{^{'}} = 2 x y + 4 y, y (2) = 1

y + 4 ln (y) = x^{2} + 4 x - 11

Solution steps

(y + 4) \cdot y^{'} (x) = 2 x y + 4 y

Solve separable ODE:

y + 4 ln (y) = x^{2} + 4 x - 11

y + 4 ln (y) = x^{2} + 4 x - 11

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x \to + 9 - lim (\frac{- 7}{( x + 9 )})

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\frac{1}{3} (y^{2} + 2)^{\frac{3}{2}}

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What is the solution for (y+4)*y^'=2xy+4y,y(2)=1 ?
The solution for (y+4)*y^'=2xy+4y,y(2)=1 is y+4ln(y)=x^2+4x-11