What is the tangent of 3y^2-2x^2=6-2xy,(3,2) ?

The tangent of 3y^2-2x^2=6-2xy,(3,2) is y= 4/9 x+2/3

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tangent of 3y^2-2x^2=6-2xy,(3,2)

tangent of

3 y^{2} - 2 x^{2} = 6 - 2 x y, (3, 2)

y = \frac{4}{9} x + \frac{2}{3}

Solution steps

Find the slope of

3 y^{2} - 2 x^{2} = 6 - 2 x y : \frac{d y}{d x} = \frac{- y + 2 x}{x + 3 y}

Compute the slope of

3 y^{2} - 2 x^{2} = 6 - 2 x y

(3, 2) : m = \frac{4}{9}

Find the line with slope m=

\frac{4}{9}

and passing through

(3, 2) : y = \frac{4}{9} x + \frac{2}{3}

y = \frac{4}{9} x + \frac{2}{3}

y = x^{2} - 11, y = 10 x

\frac{d}{d x} (\frac{x - 3}{x + 3})

\int \frac{x ^{2}}{( - x + 1 ) ( x + 1 )} d x

\int_{0}^{1} \frac{37}{4 y - 1} d y

\int_{0}^{3} arctan (x) d x

What is the tangent of 3y^2-2x^2=6-2xy,(3,2) ?
The tangent of 3y^2-2x^2=6-2xy,(3,2) is y= 4/9 x+2/3