What is the derivative of f(x)=(x^2)/(7+sqrt(x)) ?

The derivative of f(x)=(x^2)/(7+sqrt(x)) is (4x(7+sqrt(x))-x^{3/2})/(2(7+sqrt(x))^2)

What is the first derivative of f(x)=(x^2)/(7+sqrt(x)) ?

The first derivative of f(x)=(x^2)/(7+sqrt(x)) is (4x(7+sqrt(x))-x^{3/2})/(2(7+sqrt(x))^2)

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derivative of

f (x) = \frac{x ^{2}}{7 + x}

\frac{4 x ( 7 + x ) - x ^{\frac{3}{2}}}{2 ( 7 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{7 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 7 + x ) - \frac{d}{d x} ( 7 + x ) x ^{2}}{( 7 + x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7 + x) = \frac{1}{2 x}

= \frac{2 x ( 7 + x ) - \frac{1}{2 x} x ^{2}}{( 7 + x ) ^{2}}

Simplify

\frac{2 x ( 7 + x ) - \frac{1}{2 x} x ^{2}}{( 7 + x ) ^{2}} : \frac{4 x ( 7 + x ) - x ^{\frac{3}{2}}}{2 ( 7 + x ) ^{2}}

= \frac{4 x ( 7 + x ) - x ^{\frac{3}{2}}}{2 ( 7 + x ) ^{2}}

x y^{^{'}} - 2 y = 2 y x^{2}

\frac{d}{d x} ((x^{2} - 3 x)^{6} (4 - x)^{5})

x \to 2 lim (e^{\frac{1}{x - 2}})

x \to 0 lim (x \cdot cot (2 x))

\int \frac{9 - 162 x}{1 - 81 x ^{2}} d x

What is the derivative of f(x)=(x^2)/(7+sqrt(x)) ?
The derivative of f(x)=(x^2)/(7+sqrt(x)) is (4x(7+sqrt(x))-x^{3/2})/(2(7+sqrt(x))^2)
What is the first derivative of f(x)=(x^2)/(7+sqrt(x)) ?
The first derivative of f(x)=(x^2)/(7+sqrt(x)) is (4x(7+sqrt(x))-x^{3/2})/(2(7+sqrt(x))^2)