What is the slope of y=x^2-2x-3,(2,-3) ?

The slope of y=x^2-2x-3,(2,-3) is 2

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slope of y=x^2-2x-3,(2,-3)

slope

y = x^{2} - 2 x - 3, (2, - 3)

2

Solution steps

y = x^{2} - 2 x - 3

In order to find the slope of the function, take the derivative of

x^{2} - 2 x - 3

\frac{d}{d x} (x^{2} - 2 x - 3) = 2 x - 2

2 x - 2

Find the value of

2 x - 2

for

x = 2 : 2

2

\frac{\partial}{\partial x} (x y)

f (x) = x^{4} - 4 x^{3} + 8, at x = 2

\int 2 x^{3} - 6 x^{2} + 2 x - 1 + (\frac{2}{x}) d x

\frac{\partial}{\partial y} (sin (x y) + cos (x y))

\frac{d}{d x} (\frac{x + 1}{x ^{2} - 1})