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Popular >

y^'+5y=4,y(0)=0

Solution

y^{^{'}} + 5 y = 4, y (0) = 0

Solution

y = - \frac{4 e ^{- 5 t}}{5} + \frac{4}{5}

Solution steps

y^{'} (t) + 5 y = 4

Solve separable ODE:

y = - \frac{4 e ^{- 5 t}}{5} + \frac{4}{5}

y = - \frac{4 e ^{- 5 t}}{5} + \frac{4}{5}

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\frac{\partial}{\partial y} (y + e^{x})

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n = 0 \sum \infty n (\frac{1}{4})^{n}

integral of (e^x)/(3+5e^{2x)}

\int \frac{e ^{x}}{3 + 5 e ^{2 x}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+5y=4,y(0)=0 ?
The solution for y^'+5y=4,y(0)=0 is y=-(4e^{-5t})/5+4/5