What is the tangent of f(x)=(1-x)/(2x),\at x=1 ?

The tangent of f(x)=(1-x)/(2x),\at x=1 is y=-1/2 x+1/2

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tangent of f(x)=(1-x)/(2x),\at x=1

tangent of

f (x) = \frac{1 - x}{2 x}, at x = 1

y = - \frac{1}{2} x + \frac{1}{2}

Solution steps

Find the tangent point:

(1, 0)

Find the slope of

f (x) = \frac{1 - x}{2 x} : \frac{df ( x )}{d x} = - \frac{1}{2 x ^{2}}

Compute the slope of

f (x) = \frac{1 - x}{2 x}

x = 1 : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(1, 0) : y = - \frac{1}{2} x + \frac{1}{2}

y = - \frac{1}{2} x + \frac{1}{2}

\frac{d}{d x} (\frac{1}{6} (x^{2} - 4)^{\frac{3}{2}})

\int \frac{5 - 50 x}{49 - 25 x ^{2}} d x

\frac{d}{d x} (e^{2 x} x + 1)

\int_{2}^{\infty} y e^{- 8 y} d y

\frac{d}{d x} (cos^{2} (x^{2} + y^{2}))

What is the tangent of f(x)=(1-x)/(2x),\at x=1 ?
The tangent of f(x)=(1-x)/(2x),\at x=1 is y=-1/2 x+1/2