What is inverse oflaplace s/(s(s^2+s+1)) ?

The answer to inverse oflaplace s/(s(s^2+s+1)) is Undefined

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inverse oflaplace s/(s(s^2+s+1))

inverse laplace

\frac{s}{s ( s ^{2} + s + 1 )}

Undefined

Solution steps

L^{- 1} {\frac{s}{s ( s ^{2} + s + 1 )}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {s F (s)} = \frac{d}{d t} f (t) + f (0)

For

\frac{s}{s ( s ^{2} + s + 1 )} : F (s) = \frac{1}{s ( s ^{2} + s + 1 )}

= \frac{d}{d t} (L^{- 1} {\frac{1}{s ( s ^{2} + s + 1 )}}) + L^{- 1} {\frac{1}{s ( s ^{2} + s + 1 )}} (0)

L^{- 1} {\frac{1}{s ( s ^{2} + s + 1 )}} : H (t) - e^{- \frac{t}{2}} cos (\frac{3 t}{2}) - \frac{e ^{- \frac{t}{2}} sin ( \frac{3 t}{2} )}{3}

Evaluate

H (t) - e^{- \frac{t}{2}} cos (\frac{3 t}{2}) - \frac{e ^{- \frac{t}{2}} sin ( \frac{3 t}{2} )}{3}

at point

0 =

Undefined

= Undefined

\int x cos^{2} (8 x) d x

\frac{d y}{d x} = \frac{x + 2}{y}

\int \frac{1}{7 x + 3} d x

\frac{d}{d t} (\frac{2 t + 7}{2 t})

\frac{d}{d x} (- 2 tan (x))

What is inverse oflaplace s/(s(s^2+s+1)) ?
The answer to inverse oflaplace s/(s(s^2+s+1)) is Undefined