What is the integral of xcos^2(x) ?

The integral of xcos^2(x) is 1/2 x(x+1/2 sin(2x))-1/2 ((x^2)/2-1/4 cos(2x))+C

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integral of xcos^2(x)

\int x cos^{2} (x) d x

\frac{1}{2} x (x + \frac{1}{2} sin (2 x)) - \frac{1}{2} (\frac{x ^{2}}{2} - \frac{1}{4} cos (2 x)) + C

Solution steps

\int x cos^{2} (x) d x

Apply Integration By Parts

: \frac{1}{2} x (x + \frac{1}{2} sin (2 x)) - \int \frac{1}{2} (x + \frac{1}{2} sin (2 x)) d x

= \frac{1}{2} x (x + \frac{1}{2} sin (2 x)) - \int \frac{1}{2} (x + \frac{1}{2} sin (2 x)) d x

\int \frac{1}{2} (x + \frac{1}{2} sin (2 x)) d x = \frac{1}{2} (\frac{x ^{2}}{2} - \frac{1}{4} cos (2 x))

= \frac{1}{2} x (x + \frac{1}{2} sin (2 x)) - \frac{1}{2} (\frac{x ^{2}}{2} - \frac{1}{4} cos (2 x))

Add a constant to the solution

= \frac{1}{2} x (x + \frac{1}{2} sin (2 x)) - \frac{1}{2} (\frac{x ^{2}}{2} - \frac{1}{4} cos (2 x)) + C

\frac{\partial}{\partial x} (x^{2} + y^{2} - 1)

\frac{d}{d x} (sec (2 x) tan (2 x))

\frac{\partial}{\partial x} (x - z - arctan (yz))

f (x) = \frac{x ^{3}}{( x ^{2} + 4 ) ^{2}}

\frac{d}{d x} (\frac{cos ( x )}{x})

What is the integral of xcos^2(x) ?
The integral of xcos^2(x) is 1/2 x(x+1/2 sin(2x))-1/2 ((x^2)/2-1/4 cos(2x))+C