What is the derivative of-1-4sin(x) ?

The derivative of-1-4sin(x) is -4cos(x)

What is the first derivative of-1-4sin(x) ?

The first derivative of-1-4sin(x) is -4cos(x)

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\frac{d}{d x} (- 1 - 4 sin (x))

- 4 cos (x)

Solution steps

\frac{d}{d x} (- 1 - 4 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (1) - \frac{d}{d x} (4 sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (4 sin (x)) = 4 cos (x)

= - 0 - 4 cos (x)

Simplify

= - 4 cos (x)

k = 0 \sum \infty 5 x^{k}

\frac{s + 5}{s ^{2} - 4 s + 4}

\frac{d}{d x} (sin (2 arcsec (x)))

- 4 e^{(- 2 s)} \cdot \frac{1}{s - 3}

x^{(3)} + a \cdot x^{(2)} + b \cdot x + c

What is the derivative of-1-4sin(x) ?
The derivative of-1-4sin(x) is -4cos(x)
What is the first derivative of-1-4sin(x) ?
The first derivative of-1-4sin(x) is -4cos(x)