What is the integral of sin(y)cosh(x) ?

The integral of sin(y)cosh(x) is -cosh(x)cos(y)+C

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integral of sin(y)cosh(x)

\int sin (y) cosh (x) d y

- cosh (x) cos (y) + C

Solution steps

\int sin (y) cosh (x) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cosh (x) \cdot \int sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= cosh (x) (- cos (y))

Simplify

= - cosh (x) cos (y)

Add a constant to the solution

= - cosh (x) cos (y) + C

x \to 0 lim (1)

\int \frac{- ( x ^{2} - 1 ) ( 6 x ^{2} + 6 )}{x ^{2} + 1} d x

\int \frac{1}{0.15 x + 20} d x

9 y^{^{''}} + 2 y = 0

\frac{d y}{d x} = 2 x sec (y)

What is the integral of sin(y)cosh(x) ?
The integral of sin(y)cosh(x) is -cosh(x)cos(y)+C