What is the first derivative of 2x^2-1 ?

The first derivative of 2x^2-1 is 4x

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derivative of 2x^2-1

derivative of

2 x^{2} - 1

4 x

Solution steps

\frac{d}{d x} (2 x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 4 x - 0

Simplify

= 4 x

\int arctan (x + 1) d x

\int \frac{cos ( x )}{3 cos ( x ) - 5} d x

\frac{1}{s ( s ^{2} + 0.5 s + 1 )}

y^{^{'}} = \frac{1}{y} (1 - 2 x)

x + \frac{3}{x}