What is the integral of sin(x)e^{cos(x)} ?

The integral of sin(x)e^{cos(x)} is -e^{cos(x)}+C

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integral of sin(x)e^{cos(x)}

\int sin (x) e^{c o s (x)} d x

- e^{c o s (x)} + C

Solution steps

\int sin (x) e^{c o s (x)} d x

Apply u-substitution

: \int - e^{u} d u

= \int - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - e^{u}

Substitute back

u = cos (x)

= - e^{c o s (x)}

Add a constant to the solution

= - e^{c o s (x)} + C

(4 x^{2} + 9)^{6}

\int_{0}^{1} 5 x^{2} d x

31

y = 3 x^{3} - x^{2} + 3, (2, 23)

\frac{k}{( s - 4 ) ^{3}}

What is the integral of sin(x)e^{cos(x)} ?
The integral of sin(x)e^{cos(x)} is -e^{cos(x)}+C