What is the derivative of 3-1/x ?

The derivative of 3-1/x is 1/(x^2)

What is the first derivative of 3-1/x ?

The first derivative of 3-1/x is 1/(x^2)

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\frac{d}{d x} (3 - \frac{1}{x})

\frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (3 - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 0 - (- \frac{1}{x ^{2}})

Simplify

= \frac{1}{x ^{2}}

\int \frac{x ^{3}}{1 + x} d x

y^{^{''}} - y^{^{'}} - 2 y = - 6 t + 4 t^{2}

y = sin (x), (4 π, 0)

\frac{d y}{d x} = x y, y (0) = 0

f (x) = 3 x, (1, 3)

What is the derivative of 3-1/x ?
The derivative of 3-1/x is 1/(x^2)
What is the first derivative of 3-1/x ?
The first derivative of 3-1/x is 1/(x^2)