What is the derivative of 2x^3-4x+5 ?

The derivative of 2x^3-4x+5 is 6x^2-4

What is the first derivative of 2x^3-4x+5 ?

The first derivative of 2x^3-4x+5 is 6x^2-4

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\frac{d}{d x} (2 x^{3} - 4 x + 5)

6 x^{2} - 4

Solution steps

\frac{d}{d x} (2 x^{3} - 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 6 x^{2} - 4 + 0

Simplify

= 6 x^{2} - 4

x \to 0 lim (+ arctan (ln (x)))

x \to - 1 lim (11 x + 9)

\frac{t}{t - 1}

(1 + cos (t)) y^{^{'}} = (1 + e - y) sin (t)

y^{^{''}} + 4 y = 8 tan (2 x)

What is the derivative of 2x^3-4x+5 ?
The derivative of 2x^3-4x+5 is 6x^2-4
What is the first derivative of 2x^3-4x+5 ?
The first derivative of 2x^3-4x+5 is 6x^2-4