What is the derivative of f(x)=(1-3x)/(4+x) ?

The derivative of f(x)=(1-3x)/(4+x) is -(13)/((4+x)^2)

What is the first derivative of f(x)=(1-3x)/(4+x) ?

The first derivative of f(x)=(1-3x)/(4+x) is -(13)/((4+x)^2)

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derivative of

f (x) = \frac{1 - 3 x}{4 + x}

- \frac{13}{( 4 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1 - 3 x}{4 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 - 3 x ) ( 4 + x ) - \frac{d}{d x} ( 4 + x ) ( 1 - 3 x )}{( 4 + x ) ^{2}}

\frac{d}{d x} (1 - 3 x) = - 3

\frac{d}{d x} (4 + x) = 1

= \frac{( - 3 ) ( 4 + x ) - 1 \cdot ( 1 - 3 x )}{( 4 + x ) ^{2}}

Simplify

\frac{( - 3 ) ( 4 + x ) - 1 \cdot ( 1 - 3 x )}{( 4 + x ) ^{2}} : - \frac{13}{( 4 + x ) ^{2}}

= - \frac{13}{( 4 + x ) ^{2}}

\frac{d}{d t} (A t e^{- \frac{t}{3}})

sin (x)

(1, - 2), (4, 0)

x \to 6 + lim (\frac{1}{x - 6})

\int \frac{1}{( x + 4 ) ^{2} ( x - 2 )} d x

What is the derivative of f(x)=(1-3x)/(4+x) ?
The derivative of f(x)=(1-3x)/(4+x) is -(13)/((4+x)^2)
What is the first derivative of f(x)=(1-3x)/(4+x) ?
The first derivative of f(x)=(1-3x)/(4+x) is -(13)/((4+x)^2)