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Popular >

h^'=2t^2-3e^t

Solution

h^{^{'}} = 2 t^{2} - 3 e^{t}

Solution

h (t) = \frac{2 t ^{3}}{3} - 3 e^{t} + c_{1}

Solution steps

h^{'} (t) = 2 t^{2} - 3 e^{t}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

h (t) = \int 2 t^{2} - 3 e^{t} d t

\int 2 t^{2} - 3 e^{t} d t = \frac{2 t ^{3}}{3} - 3 e^{t} + c_{1}

h (t) = \frac{2 t ^{3}}{3} - 3 e^{t} + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for h^'=2t^2-3e^t ?
The solution for h^'=2t^2-3e^t is h(t)=(2t^3)/3-3e^t+c_{1}