What is the derivative of x^3b^5+y^4b+z^6 ?

The derivative of x^3b^5+y^4b+z^6 is 3b^5x^2

What is the first derivative of x^3b^5+y^4b+z^6 ?

The first derivative of x^3b^5+y^4b+z^6 is 3b^5x^2

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derivative of

x^{3} b^{5} + y^{4} b + z^{6}

3 b^{5} x^{2}

Solution steps

\frac{d}{d x} (x^{3} b^{5} + y^{4} b + z^{6})

Treat

b, y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3} b^{5}) + \frac{d}{d x} (y^{4} b) + \frac{d}{d x} (z^{6})

\frac{d}{d x} (x^{3} b^{5}) = 3 b^{5} x^{2}

\frac{d}{d x} (y^{4} b) = 0

\frac{d}{d x} (z^{6}) = 0

= 3 b^{5} x^{2} + 0 + 0

Simplify

= 3 b^{5} x^{2}

\int - sin (t) cos (t) d t

\int \frac{ln ( x ) + 9}{x} d x

\frac{\partial}{\partial x} (2 x^{2} + y)

tan (2 (x + 1))

x \to 1 + lim (\frac{x + 2}{1 - x})

What is the derivative of x^3b^5+y^4b+z^6 ?
The derivative of x^3b^5+y^4b+z^6 is 3b^5x^2
What is the first derivative of x^3b^5+y^4b+z^6 ?
The first derivative of x^3b^5+y^4b+z^6 is 3b^5x^2