What is the derivative of f(x)=x-1 ?

The derivative of f(x)=x-1 is 1

What is the first derivative of f(x)=x-1 ?

The first derivative of f(x)=x-1 is 1

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derivative of

f (x) = x - 1

1

Solution steps

\frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - 0

Simplify

= 1

\frac{\partial}{\partial x} (sin (\frac{2 y}{x}))

\int - \frac{29}{x ^{30}} d x

e^{- t} cos (t)

y^{^{''}} + y = 4 csc^{2} (x)

3 x d y + 2 y d x = 0

What is the derivative of f(x)=x-1 ?
The derivative of f(x)=x-1 is 1
What is the first derivative of f(x)=x-1 ?
The first derivative of f(x)=x-1 is 1