What is the integral of ((x^2-x+5)/x) ?

The integral of ((x^2-x+5)/x) is (x^2)/2-x+5ln|x|+C

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integral of ((x^2-x+5)/x)

\int (\frac{x ^{2} - x + 5}{x}) d x

\frac{x ^{2}}{2} - x + 5 ln ∣ x ∣ + C

Solution steps

\int \frac{x ^{2} - x + 5}{x} d x

Expand

\frac{x ^{2} - x + 5}{x} : x - 1 + \frac{5}{x}

= \int x - 1 + \frac{5}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x - \int 1 d x + \int \frac{5}{x} d x

\int x d x = \frac{x ^{2}}{2}

\int 1 d x = x

\int \frac{5}{x} d x = 5 ln ∣ x ∣

= \frac{x ^{2}}{2} - x + 5 ln ∣ x ∣

Add a constant to the solution

= \frac{x ^{2}}{2} - x + 5 ln ∣ x ∣ + C

\frac{d y}{d x} = - y + 5

x \to - 7 lim (\frac{x + 3}{x + 7})

(4.4) (2.4)

x \to - 4 lim (2)

\int \frac{10}{( x - 2 ) ( x + 8 )} d x

What is the integral of ((x^2-x+5)/x) ?
The integral of ((x^2-x+5)/x) is (x^2)/2-x+5ln|x|+C