What is the integral from 1 to 10 of 9/(x^3) ?

The integral from 1 to 10 of 9/(x^3) is 891/200

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integral from 1 to 10 of 9/(x^3)

\int_{1}^{10} \frac{9}{x ^{3}} d x

\frac{891}{200}

Decimal Notation

4.455

Solution steps

\int_{1}^{10} \frac{9}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{1}^{10} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{10}

= 9 [- \frac{1}{2 x ^{2}}]_{1}^{10}

Compute the boundaries:

\frac{99}{200}

= 9 \cdot \frac{99}{200}

Simplify

= \frac{891}{200}

\int \frac{sin ( x )}{x} d x

x = 9 y^{2}, x = 16 + 5 y^{2}

y = e^{7 x}

(1 - x^{2})^{- \frac{1}{2}}, 0

x \to 3 lim (- 5)

What is the integral from 1 to 10 of 9/(x^3) ?
The integral from 1 to 10 of 9/(x^3) is 891/200