What is the derivative of tan^2(sin(x)+cos(2x)) ?

The derivative of tan^2(sin(x)+cos(2x)) is 2tan(sin(x))sec^2(sin(x))cos(x)-sin(2x)*2

What is the first derivative of tan^2(sin(x)+cos(2x)) ?

The first derivative of tan^2(sin(x)+cos(2x)) is 2tan(sin(x))sec^2(sin(x))cos(x)-sin(2x)*2

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\frac{d}{d x} (tan^{2} (sin (x)) + cos (2 x))

2 tan (sin (x)) sec^{2} (sin (x)) cos (x) - sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (tan^{2} (sin (x)) + cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (tan^{2} (sin (x))) + \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (tan^{2} (sin (x))) = 2 tan (sin (x)) sec^{2} (sin (x)) cos (x)

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 tan (sin (x)) sec^{2} (sin (x)) cos (x) - sin (2 x) \cdot 2

f (x) = arctan (\frac{x}{2})

4 y^{^{''}} = y

x \to \infty lim (e^{5 x})

\int (x + \frac{1}{x}) (x - \frac{2}{x}) d x

f (x) = (5 x^{2} - 3) (x^{2} + x + 4)

What is the derivative of tan^2(sin(x)+cos(2x)) ?
The derivative of tan^2(sin(x)+cos(2x)) is 2tan(sin(x))sec^2(sin(x))cos(x)-sin(2x)*2
What is the first derivative of tan^2(sin(x)+cos(2x)) ?
The first derivative of tan^2(sin(x)+cos(2x)) is 2tan(sin(x))sec^2(sin(x))cos(x)-sin(2x)*2