What is the derivative of arctan(x+x-1) ?

The derivative of arctan(x+x-1) is 1/(x^2+1)+1

What is the first derivative of arctan(x+x-1) ?

The first derivative of arctan(x+x-1) is 1/(x^2+1)+1

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\frac{d}{d x} (arctan (x) + x - 1)

\frac{1}{x ^{2} + 1} + 1

Solution steps

\frac{d}{d x} (arctan (x) + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arctan (x)) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (arctan (x)) = \frac{1}{x ^{2} + 1}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{1}{x ^{2} + 1} + 1 - 0

Simplify

= \frac{1}{x ^{2} + 1} + 1

y^{^{''}} - 16 y^{^{'}} + 73 = 0, y (0) = 6, y^{^{'}} (0) = 6

\frac{d}{d x} (\frac{1}{2} (4 x^{2} + x)^{- 3})

y^{^{'}} = - 3 y

\frac{\partial}{\partial x} (e^{6 x + 4 y})

\int_{0}^{1} \frac{4}{4 - x ^{2}} d x

What is the derivative of arctan(x+x-1) ?
The derivative of arctan(x+x-1) is 1/(x^2+1)+1
What is the first derivative of arctan(x+x-1) ?
The first derivative of arctan(x+x-1) is 1/(x^2+1)+1