What is the integral from pi to 0 of sin(x) ?

The integral from pi to 0 of sin(x) is -2

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integral from pi to 0 of sin(x)

\int_{π}^{0} sin (x) d x

- 2

Solution steps

\int_{π}^{0} sin (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= - 2

\int \frac{x ^{2}}{2 ( 1 + x ^{2} )} d x

\frac{d}{d x} (y + x (ln (x) - ln (y) - 1))

\int 4 x - 5 d x

\frac{s ^{3}}{s + 2}

\frac{d}{d x} (ln (2 x - y))

What is the integral from pi to 0 of sin(x) ?
The integral from pi to 0 of sin(x) is -2