What is the derivative of (x^3/6) ?

The derivative of (x^3/6) is (x^2)/2

What is the first derivative of (x^3/6) ?

The first derivative of (x^3/6) is (x^2)/2

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\frac{d}{d x} (\frac{x ^{3}}{6})

\frac{x ^{2}}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{6} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{6} \cdot 3 x^{3 - 1} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

\int_{0}^{1} \frac{1}{5 x - 3} d x

2 y^{^{''}} + y^{^{'}} - y = x + 1

x \to 3 lim (x^{2} + 4 x - 3)

\frac{d}{d x} (x^{3} - 4)

\int (1 - x)^{5} (x + 1)^{2} d x

What is the derivative of (x^3/6) ?
The derivative of (x^3/6) is (x^2)/2
What is the first derivative of (x^3/6) ?
The first derivative of (x^3/6) is (x^2)/2