What is the derivative of x^3-4 ?

The derivative of x^3-4 is 3x^2

What is the first derivative of x^3-4 ?

The first derivative of x^3-4 is 3x^2

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\frac{d}{d x} (x^{3} - 4)

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4) = 0

= 3 x^{2} - 0

Simplify

= 3 x^{2}

\int (1 - x)^{5} (x + 1)^{2} d x

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