en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x=0,y=x^2,y=x+2

Solution

area

x = 0, y = x^{2}, y = x + 2

Solution

\frac{9}{2}

+1

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} x^{2} - (x + 2) d x

Solve

\int_{- 1}^{2} x^{2} - (x + 2) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

Popular Examples

limit as x approaches-1 of-6

x \to - 1 lim (- 6)

derivative of sqrt(9x-(sin^2(2x)))derivative of

9 x - (sin^{2} (2 x))

(\partial)/(\partial x)(xsin(y))

\frac{\partial}{\partial x} (x sin (y))

area x^2,8-x^2,4x+12 area

x^{2}, 8 - x^{2}, 4 x + 12

derivative of 7^{x^2-x}derivative of

7^{x^{2} - x}

Frequently Asked Questions (FAQ)

What is area x=0,y=x^2,y=x+2 ?
The answer to area x=0,y=x^2,y=x+2 is 9/2