What is the solution for x(dy)/(dx)-y=2x^2y^2 ?

The solution for x(dy)/(dx)-y=2x^2y^2 is y=(3x)/(-2x^3+c_{1)}

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x(dy)/(dx)-y=2x^2y^2

x \frac{d y}{d x} - y = 2 x^{2} y^{2}

y = \frac{3 x}{- 2 x ^{3} + c _{1}}

Solution steps

x \frac{d y}{d x} - y = 2 x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{3 x}{- 2 x ^{3} + c _{1}}

y = \frac{3 x}{- 2 x ^{3} + c _{1}}

sin (2) x^{3}

x \to 2 + lim (x - 2)

f (x) = arccsc (x)

f (x) = ln (tan (2 x)), at x = \frac{π}{8}

\frac{d}{d x} (\frac{e ^{x} + 1}{e ^{2 x} - 5 e ^{x} + 6})

What is the solution for x(dy)/(dx)-y=2x^2y^2 ?
The solution for x(dy)/(dx)-y=2x^2y^2 is y=(3x)/(-2x^3+c_{1)}