What is the sum from n=1 to infinity of ((-3)^n)/n ?

The sum from n=1 to infinity of ((-3)^n)/n is diverges

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sum from n=1 to infinity of ((-3)^n)/n

n = 1 \sum \infty \frac{( - 3 ) ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{( - 3 ) ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

\frac{d}{d x} (x - x^{- 1})

y^{^{'}} - \frac{3}{x} y = \frac{y ^{4}}{x ^{2}}

\frac{d}{d s} (s i)

\frac{x ^{2} + 1}{x}

\int sin (x) cos (n) x d x

What is the sum from n=1 to infinity of ((-3)^n)/n ?
The sum from n=1 to infinity of ((-3)^n)/n is diverges