What is the derivative of f(x)=(sin(5x))/(3x) ?

The derivative of f(x)=(sin(5x))/(3x) is (5xcos(5x)-sin(5x))/(3x^2)

What is the first derivative of f(x)=(sin(5x))/(3x) ?

The first derivative of f(x)=(sin(5x))/(3x) is (5xcos(5x)-sin(5x))/(3x^2)

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derivative of

f (x) = \frac{sin ( 5 x )}{3 x}

\frac{5 x cos ( 5 x ) - sin ( 5 x )}{3 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{sin ( 5 x )}{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (\frac{sin ( 5 x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{3} \cdot \frac{\frac{d}{d x} ( sin ( 5 x ) ) x - \frac{d x}{d x} sin ( 5 x )}{x ^{2}}

\frac{d}{d x} (sin (5 x)) = cos (5 x) \cdot 5

\frac{d x}{d x} = 1

= \frac{1}{3} \cdot \frac{cos ( 5 x ) \cdot 5 x - 1 \cdot sin ( 5 x )}{x ^{2}}

Simplify

\frac{1}{3} \cdot \frac{cos ( 5 x ) \cdot 5 x - 1 \cdot sin ( 5 x )}{x ^{2}} : \frac{5 x cos ( 5 x ) - sin ( 5 x )}{3 x ^{2}}

= \frac{5 x cos ( 5 x ) - sin ( 5 x )}{3 x ^{2}}

\frac{7}{1 - x}

\frac{d}{d x} (\frac{12}{( 1 - x ) ^{5}})

n = 3 \sum \infty \frac{x ^{n}}{n !}

\int \frac{1}{1 - 49 x ^{2}} d x

\int \frac{x ^{2} - 25}{x - 5} d x

What is the derivative of f(x)=(sin(5x))/(3x) ?
The derivative of f(x)=(sin(5x))/(3x) is (5xcos(5x)-sin(5x))/(3x^2)
What is the first derivative of f(x)=(sin(5x))/(3x) ?
The first derivative of f(x)=(sin(5x))/(3x) is (5xcos(5x)-sin(5x))/(3x^2)