What is (\partial)/(\partial x)(3x^2-3y) ?

The answer to (\partial)/(\partial x)(3x^2-3y) is 6x

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(\partial)/(\partial x)(3x^2-3y)

\frac{\partial}{\partial x} (3 x^{2} - 3 y)

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 3 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (3 y)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (3 y) = 0

= 6 x - 0

Simplify

= 6 x

\frac{d}{d x} (\frac{1}{1 + x + x ^{2}})

(- x^{2})^{^{'}}

\frac{d}{d x} (x e^{x + 1})

(2 + x) \frac{d y}{d x} = 3 y

\int_{0}^{2} 2 t^{3} d t

What is (\partial)/(\partial x)(3x^2-3y) ?
The answer to (\partial)/(\partial x)(3x^2-3y) is 6x