What is the derivative of sqrt(8t^2+9) ?

The derivative of sqrt(8t^2+9) is (8t)/(sqrt(8t^2+9))

What is the first derivative of sqrt(8t^2+9) ?

The first derivative of sqrt(8t^2+9) is (8t)/(sqrt(8t^2+9))

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derivative of

8 t^{2} + 9

\frac{8 t}{8 t ^{2} + 9}

Solution steps

\frac{d}{d t} (8 t^{2} + 9)

Apply the chain rule:

\frac{1}{2 8 t ^{2} + 9} \frac{d}{d t} (8 t^{2} + 9)

= \frac{1}{2 8 t ^{2} + 9} \frac{d}{d t} (8 t^{2} + 9)

\frac{d}{d t} (8 t^{2} + 9) = 16 t

= \frac{1}{2 8 t ^{2} + 9} \cdot 16 t

Simplify

\frac{1}{2 8 t ^{2} + 9} \cdot 16 t : \frac{8 t}{8 t ^{2} + 9}

= \frac{8 t}{8 t ^{2} + 9}

\int x^{2} e^{1 x} d x

\int \frac{e ^{x} + e ^{2 x}}{e ^{x}} d x

e^{- 2 t} sin (t)

x \to a lim (\frac{3}{0})

\frac{20}{s ( s + 10 )}

What is the derivative of sqrt(8t^2+9) ?
The derivative of sqrt(8t^2+9) is (8t)/(sqrt(8t^2+9))
What is the first derivative of sqrt(8t^2+9) ?
The first derivative of sqrt(8t^2+9) is (8t)/(sqrt(8t^2+9))