What is the sum from n=0 to infinity of 1/(7^n) ?

The sum from n=0 to infinity of 1/(7^n) is 7/6

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sum from n=0 to infinity of 1/(7^n)

n = 0 \sum \infty \frac{1}{7 ^{n}}

\frac{7}{6}

Solution steps

n = 0 \sum \infty \frac{1}{7 ^{n}}

Apply Series Geometric Test:

\frac{7}{6}

= \frac{7}{6}

\frac{d y}{d x} = \frac{( x + sec ^{2} ( x ) )}{y}

\int \frac{1}{1 + e ^{a x}} d x

\int \frac{x}{x ^{4} + 16} d x

2 y^{^{'''}} - 3 y^{^{''}} - 18 y^{^{'}} - 8 y = 0

y = 3 x^{2} - 12, y = 0

What is the sum from n=0 to infinity of 1/(7^n) ?
The sum from n=0 to infinity of 1/(7^n) is 7/6