What is the solution for (dy)/(dx)y=(3x-2x^2)^3 ?

The solution for (dy)/(dx)y=(3x-2x^2)^3 is

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(dy)/(dx)y=(3x-2x^2)^3

\frac{d y}{d x} y = (3 x - 2 x^{2})^{3}

y = \frac{27 x ^{4}}{2} - \frac{108 x ^{5}}{5} + 12 x^{6} - \frac{16 x ^{7}}{7} + c_{1}, y = - \frac{27 x ^{4}}{2} - \frac{108 x ^{5}}{5} + 12 x^{6} - \frac{16 x ^{7}}{7} + c_{1}

Solution steps

\frac{d y}{d x} y = (3 x - 2 x^{2})^{3}

Solve separable ODE:

y = \frac{27 x ^{4}}{2} - \frac{108 x ^{5}}{5} + 12 x^{6} - \frac{16 x ^{7}}{7} + c_{1}, y = - \frac{27 x ^{4}}{2} - \frac{108 x ^{5}}{5} + 12 x^{6} - \frac{16 x ^{7}}{7} + c_{1}

y = \frac{27 x ^{4}}{2} - \frac{108 x ^{5}}{5} + 12 x^{6} - \frac{16 x ^{7}}{7} + c_{1}, y = - \frac{27 x ^{4}}{2} - \frac{108 x ^{5}}{5} + 12 x^{6} - \frac{16 x ^{7}}{7} + c_{1}

f (x) = \frac{x ^{2}}{( 3 + x )}

e^{\frac{1}{6} x^{6}}, 0

x \to - 6 - lim (- \frac{1}{x + 6})

\int_{1}^{3} (3 - x)^{2} d x

\frac{d}{d x} (\frac{1}{e ^{x} + e ^{- x}})

What is the solution for (dy)/(dx)y=(3x-2x^2)^3 ?
The solution for (dy)/(dx)y=(3x-2x^2)^3 is