What is the limit as x approaches 2pi of 1/(sin(x)) ?

The limit as x approaches 2pi of 1/(sin(x)) is diverges

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limit as x approaches 2pi of 1/(sin(x))

x \to 2 π lim (\frac{1}{sin ( x )})

diverges

Solution steps

x \to 2 π lim (\frac{1}{sin ( x )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 π + lim (\frac{1}{sin ( x )}) = \infty

x \to 2 π - lim (\frac{1}{sin ( x )}) = - \infty

= diverges

sin (2 x)

\frac{d}{d x} (\frac{x ^{4} - 4 x + 3}{x + 1})

(y)^{^{'}}

\int_{x}^{x^{2}} t^{2} d t

\frac{d y}{d x} 7 x + y = x - 6 x

What is the limit as x approaches 2pi of 1/(sin(x)) ?
The limit as x approaches 2pi of 1/(sin(x)) is diverges