What is the integral of xsin(4x^2) ?

The integral of xsin(4x^2) is -1/8 cos(4x^2)+C

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integral of xsin(4x^2)

\int x sin (4 x^{2}) d x

- \frac{1}{8} cos (4 x^{2}) + C

Solution steps

\int x sin (4 x^{2}) d x

Apply u-substitution

: \int \frac{sin ( u )}{8} d u

= \int \frac{sin ( u )}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{8} (- cos (u))

Substitute back

u = 4 x^{2}

= \frac{1}{8} (- cos (4 x^{2}))

Simplify

= - \frac{1}{8} cos (4 x^{2})

Add a constant to the solution

= - \frac{1}{8} cos (4 x^{2}) + C

x \to - 2 lim (4 - 2 x)

\frac{\partial}{\partial x} ((3 x - x^{2}) y e^{- y})

x \to 0 lim (x^{2} cos (\frac{7}{x}))

(4 e^{x})^{^{'}}

\frac{7 x}{e ^{x}}

What is the integral of xsin(4x^2) ?
The integral of xsin(4x^2) is -1/8 cos(4x^2)+C