What is the derivative of f(x)=5+x^2 ?

The derivative of f(x)=5+x^2 is 2x

What is the first derivative of f(x)=5+x^2 ?

The first derivative of f(x)=5+x^2 is 2x

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derivative of

f (x) = 5 + x^{2}

2 x

Solution steps

\frac{d}{d x} (5 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (5) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

\int_{0}^{\frac{1}{2}} t^{2} d t

\frac{\partial}{\partial x} (8 + e^{- x y} cos (y))

f (x) = \frac{1}{2 + 3 x}, (2, \frac{1}{8})

y = 1 - 2 x

g (x) = (x^{2} + 1)^{3} (x^{2} + 2)^{6}

What is the derivative of f(x)=5+x^2 ?
The derivative of f(x)=5+x^2 is 2x
What is the first derivative of f(x)=5+x^2 ?
The first derivative of f(x)=5+x^2 is 2x