What is the derivative of xy^3-x^2 ?

The derivative of xy^3-x^2 is y^3+3xy^2(dy)/(dx)-2x

What is the first derivative of xy^3-x^2 ?

The first derivative of xy^3-x^2 is y^3+3xy^2(dy)/(dx)-2x

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\frac{d}{d x} (x y^{3} - x^{2})

y^{3} + 3 x y^{2} \frac{d y}{d x} - 2 x

Solution steps

\frac{d}{d x} (x y^{3} - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x y^{3}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (x y^{3}) = y^{3} + 3 x y^{2} \frac{d y}{d x}

\frac{d}{d x} (x^{2}) = 2 x

= y^{3} + 3 x y^{2} \frac{d y}{d x} - 2 x

f (x) = 2 (x^{3} - x)^{4}

\frac{\partial}{\partial y} (sin^{2} (x y))

y^{^{'}} + \frac{4 y}{x} = - \frac{3}{x}, y (1) = - 2

\int - 2 cos (\frac{x}{2}) d x

x \to 2 lim (x^{2} + 3 x)

What is the derivative of xy^3-x^2 ?
The derivative of xy^3-x^2 is y^3+3xy^2(dy)/(dx)-2x
What is the first derivative of xy^3-x^2 ?
The first derivative of xy^3-x^2 is y^3+3xy^2(dy)/(dx)-2x