What is the derivative of f(x)= 2/(3x) ?

The derivative of f(x)= 2/(3x) is -2/(3x^2)

What is the first derivative of f(x)= 2/(3x) ?

The first derivative of f(x)= 2/(3x) is -2/(3x^2)

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derivative of

f (x) = \frac{2}{3 x}

- \frac{2}{3 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{3} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{3} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{2}{3} (- 1 \cdot x^{- 1 - 1}) : - \frac{2}{3 x ^{2}}

= - \frac{2}{3 x ^{2}}

\frac{d}{d x} (\frac{3 x ^{2}}{x ^{2} - 4})

\frac{d y}{d x} = cos (x - y)

n = 0 \sum \infty \frac{n + 6}{6}

\frac{\partial}{\partial x} (e^{x^{2} y^{3}})

\frac{d}{d x} (12 e^{2} x)

What is the derivative of f(x)= 2/(3x) ?
The derivative of f(x)= 2/(3x) is -2/(3x^2)
What is the first derivative of f(x)= 2/(3x) ?
The first derivative of f(x)= 2/(3x) is -2/(3x^2)