What is the solution for y^{''}+8y+16y=0 ?

The solution for y^{''}+8y+16y=0 is y=c_{1}cos(2sqrt(6)t)+c_{2}sin(2sqrt(6)t)

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y^{''}+8y+16y=0

y^{^{''}} + 8 y + 16 y = 0

y = c_{1} cos (26 t) + c_{2} sin (26 t)

Solution steps

y^{''} (t) + 8 y + 16 y = 0

Solve linear ODE:

y = c_{1} cos (26 t) + c_{2} sin (26 t)

y = c_{1} cos (26 t) + c_{2} sin (26 t)

n = 1 \sum \infty n e^{9 n}

\int (x + 1)^{- 1} d x

x + 3, \frac{x + 3}{2}

\frac{d y}{d x} = \frac{5 y}{x}

\frac{d}{d x} (\frac{ln ( x )}{x ^{12}})

What is the solution for y^{''}+8y+16y=0 ?
The solution for y^{''}+8y+16y=0 is y=c_{1}cos(2sqrt(6)t)+c_{2}sin(2sqrt(6)t)