What is the derivative of y=1-x-x^2 ?

The derivative of y=1-x-x^2 is -2x-1

What is the first derivative of y=1-x-x^2 ?

The first derivative of y=1-x-x^2 is -2x-1

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derivative of

y = 1 - x - x^{2}

- 2 x - 1

Solution steps

\frac{d}{d x} (1 - x - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d x}{d x} - \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2}) = 2 x

= 0 - 1 - 2 x

Simplify

= - 2 x - 1

\int \frac{x ^{4}}{4} + cosh (x) + C d x

y = e^{2} + 2 x

x \to 0 lim (\frac{e ^{x} - 1}{15 x})

\frac{d}{d x} (\frac{e ^{a x} - e ^{- a x}}{e ^{a x} + e ^{- a x}})

\int 2 x e^{2} x d x

What is the derivative of y=1-x-x^2 ?
The derivative of y=1-x-x^2 is -2x-1
What is the first derivative of y=1-x-x^2 ?
The first derivative of y=1-x-x^2 is -2x-1