What is the derivative of (2x-3^{ln(x)}) ?

The derivative of (2x-3^{ln(x)}) is x^{ln(2x-3)}((ln(2x-3))/x+(2ln(x))/(2x-3))

What is the first derivative of (2x-3^{ln(x)}) ?

The first derivative of (2x-3^{ln(x)}) is x^{ln(2x-3)}((ln(2x-3))/x+(2ln(x))/(2x-3))

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\frac{d}{d x} ((2 x - 3)^{l n (x)})

x^{l n (2 x - 3)} (\frac{ln ( 2 x - 3 )}{x} + \frac{2 ln ( x )}{2 x - 3})

Solution steps

\frac{d}{d x} ((2 x - 3)^{l n (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

(2 x - 3)^{l n (x)} = e^{l n (x) l n (2 x - 3)}

= \frac{d}{d x} (e^{l n (x) l n (2 x - 3)})

Apply the chain rule:

e^{l n (x) l n (2 x - 3)} \frac{d}{d x} (ln (x) ln (2 x - 3))

= e^{l n (x) l n (2 x - 3)} \frac{d}{d x} (ln (x) ln (2 x - 3))

\frac{d}{d x} (ln (x) ln (2 x - 3)) = \frac{ln ( 2 x - 3 )}{x} + \frac{2 ln ( x )}{2 x - 3}

= e^{l n (x) l n (2 x - 3)} (\frac{ln ( 2 x - 3 )}{x} + \frac{2 ln ( x )}{2 x - 3})

e^{l n (x) l n (2 x - 3)} = x^{l n (2 x - 3)}

= x^{l n (2 x - 3)} (\frac{ln ( 2 x - 3 )}{x} + \frac{2 ln ( x )}{2 x - 3})

\frac{d}{d x} (x^{3} y - 2 x^{2} + y^{4})

\int e^{- \frac{y}{x}} d y

\int \frac{sin ( x )}{1 - sin ^{2} ( x )} d x

f (x) = \frac{1 - cos ( x )}{x}

\int_{0}^{4} \frac{x}{2} d x

What is the derivative of (2x-3^{ln(x)}) ?
The derivative of (2x-3^{ln(x)}) is x^{ln(2x-3)}((ln(2x-3))/x+(2ln(x))/(2x-3))
What is the first derivative of (2x-3^{ln(x)}) ?
The first derivative of (2x-3^{ln(x)}) is x^{ln(2x-3)}((ln(2x-3))/x+(2ln(x))/(2x-3))