What is the limit as x approaches 1 of sqrt(x+8) ?

The limit as x approaches 1 of sqrt(x+8) is 3

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limit as x approaches 1 of sqrt(x+8)

x \to 1 lim (x + 8)

3

Solution steps

x \to 1 lim (x + 8)

Plug in the value

x = 1

= 1 + 8

Simplify

1 + 8 : 3

= 3

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\frac{d ^{2}}{d x ^{2}} (\frac{x ^{3}}{x ^{2} - 1})

n = 1 \sum \infty \frac{1}{3 ^{n} - 5}

2 + \frac{3}{1 + ( x + 1 ) ^{2}}

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What is the limit as x approaches 1 of sqrt(x+8) ?
The limit as x approaches 1 of sqrt(x+8) is 3