What is the derivative of-5xy(x+y+6) ?

The derivative of-5xy(x+y+6) is -5(x^2(dy)/(dx)+2xy+2xy(dy)/(dx)+y^2)

What is the first derivative of-5xy(x+y+6) ?

The first derivative of-5xy(x+y+6) is -5(x^2(dy)/(dx)+2xy+2xy(dy)/(dx)+y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- 5 x y (x + y) + 6)

- 5 (x^{2} \frac{d y}{d x} + 2 x y + 2 x y \frac{d y}{d x} + y^{2})

Solution steps

\frac{d}{d x} (- 5 x y (x + y) + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (5 x y (x + y)) + \frac{d}{d x} (6)

\frac{d}{d x} (5 x y (x + y)) = 5 (x^{2} \frac{d y}{d x} + 2 x y + 2 x y \frac{d y}{d x} + y^{2})

\frac{d}{d x} (6) = 0

= - 5 (x^{2} \frac{d y}{d x} + 2 x y + 2 x y \frac{d y}{d x} + y^{2}) + 0

Simplify

= - 5 (x^{2} \frac{d y}{d x} + 2 x y + 2 x y \frac{d y}{d x} + y^{2})

\frac{\partial}{\partial x} (\frac{x}{a})

\int - \frac{25}{x ^{26}} d x

t^{2} \cdot y^{^{'}} + t \cdot y = 7

\int x^{3} cos (x^{4}) d x

\frac{\partial}{\partial x} (cos (e^{- x^{2}}))

What is the derivative of-5xy(x+y+6) ?
The derivative of-5xy(x+y+6) is -5(x^2(dy)/(dx)+2xy+2xy(dy)/(dx)+y^2)
What is the first derivative of-5xy(x+y+6) ?
The first derivative of-5xy(x+y+6) is -5(x^2(dy)/(dx)+2xy+2xy(dy)/(dx)+y^2)